tag:blogger.com,1999:blog-1841626496323335774.post7590334454994037562..comments2023-05-30T08:51:36.400-04:00Comments on AaronDelp.com: How Cisco UCS Deals with Split BrainsAaron Delphttp://www.blogger.com/profile/04330656671495950454noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-1841626496323335774.post-3892793428406093442010-02-24T11:47:38.575-05:002010-02-24T11:47:38.575-05:00Perfect, I see you also clarified it on the blog, ...Perfect, I see you also clarified it on the blog, makes perfect sense now :)<br /><br />Thanks...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1841626496323335774.post-17801642704368300032010-02-22T09:46:34.564-05:002010-02-22T09:46:34.564-05:00Sorry for the confusion. I'll see if I can cl...Sorry for the confusion. I'll see if I can clarify the point. What I mean is if an even number of chassis, it will drop the last one as a quorum node. So, if you had 10 chassis, 9 would be quorum nodes. This way you will always have an odd number of quorum nodes.<br /><br />Make sense?Aaron Delphttps://www.blogger.com/profile/04330656671495950454noreply@blogger.comtag:blogger.com,1999:blog-1841626496323335774.post-15000341381807571992010-02-22T08:47:29.680-05:002010-02-22T08:47:29.680-05:00Thanks for the nice post Aaron. I have a few quest...Thanks for the nice post Aaron. I have a few questions though:<br /><br />1) What exactly do you mean when you say that the odd numbered chassis are chorum chassis. Does that mean that the even number chassis are non-chorum chassis?<br /><br />2) So what in case we have 10 chassis, & 5 are chorum while 5 are non-chorum chassis, how would be the contention solved.<br /><br />Thanks again for Anonymousnoreply@blogger.com